SQL Server DATEDIFF() Function
THE WORLD'S LARGEST WEB DEVELOPER SITE

SQL Server DATEDIFF() Function

❮ SQL Server Functions

Example

Return the difference between two date values, in years:

SELECT DATEDIFF(year, '2017/08/25', '2011/08/25') AS DateDiff;
Try it Yourself »

Definition and Usage

The DATEDIFF() function returns the difference between two date values, based on the interval specified.

Syntax

DATEDIFF(interval, date1, date2)

Parameter Values

Parameter Description
interval Required. The time/date part to return. Can be one of the following values:
  • year, yyyy, yy = Year
  • quarter, qq, q = Quarter
  • month, mm, m = month
  • dayofyear = Day of the year
  • day, dy, y = Day
  • week, ww, wk = Week
  • weekday, dw, w = Weekday
  • hour, hh = hour
  • minute, mi, n = Minute
  • second, ss, s = Second
  • millisecond, ms = Millisecond
date1, date2 Required. The two dates to calculate the difference between

Technical Details

Works in: SQL Server 2014, SQL Server 2012, SQL Server 2008 R2, SQL Server 2008, SQL Server 2005

More Examples

Example

Return the difference between two date values, in months:

SELECT DATEDIFF(month, '2017/08/25', '2011/08/25') AS DateDiff;
Try it Yourself »

Example

Return the difference between two date values, in hours:

SELECT DATEDIFF(hour, '2017/08/25 07:00', '2017/08/25 12:45') AS DateDiff;
Try it Yourself »

❮ SQL Server Functions